Questions: We now have the sem-perimeter and the area of the quadrilateral. To find the radius (f) of the inscribed circle, we will use the relationship between the area, sem-perimeter, and the radius of the incircle: λ=sr
Rearranging the formula to isolate r, r=d / !
Substituting the values of A and s: r=inat/46
Evaluating the expression: r=7.65 (approximately)
Therefore, the radius of the circular fountain that can be inscribed in the quadrilateral land plot is approximately 7.06 units.
Transcript text: We now have the sem-perimeter and the area of the quadrilateral. To find the radius ($f$) of the inscribed circle, we will use the relationship between the area, sem-perimeter, and the radius of the incircle: $\lambda=\mathrm{sr}$
Rearranging the formula to isolate $\mathrm{r}, \mathrm{r}=\frac{d}{\text { ! }}$
Substituting the values of $A$ and $s: r=\frac{i n a t}{46}$
Evaluating the expression: $r=7,65$ (approximately)
Therefore, the radius of the circular fountain that can be inscribed in the quadrilateral land plot is approximately 7.06 units.
Solution
Solution Steps
To solve the given problem, we need to review the steps provided and check for mathematical correctness. The problem involves finding the radius of an inscribed circle in a quadrilateral using the relationship between the area, semi-perimeter, and the radius of the incircle.
Identify the formula for the radius of the incircle: \( r = \frac{A}{s} \), where \( A \) is the area and \( s \) is the semi-perimeter.
Substitute the given values into the formula.
Evaluate the expression to find the radius.
Step 1: Identify the Formula
To find the radius \( r \) of the inscribed circle in a quadrilateral, we use the formula:
\[
r = \frac{A}{s}
\]
where \( A \) is the area and \( s \) is the semi-perimeter.
Step 2: Substitute the Values
Given that both the area \( A \) and the semi-perimeter \( s \) are equal to 46, we substitute these values into the formula:
\[
r = \frac{46}{46}
\]
Step 3: Evaluate the Expression
Calculating the above expression gives:
\[
r = 1.0
\]
Final Answer
The radius of the inscribed circle is approximately \\(\boxed{r = 1.00}\\).