First, simplify the given equation: \[ 2 - [3 - (3 - x)] = 3x - (4 + x) \]
Simplify the left-hand side (LHS): \[ 2 - [3 - 3 + x] = 2 - [x] = 2 - x \]
Simplify the right-hand side (RHS): \[ 3x - 4 - x = 2x - 4 \]
Now the equation becomes: \[ 2 - x = 2x - 4 \]
Combine like terms: \[ 2 + 4 = 2x + x \] \[ 6 = 3x \] \[ x = 2 \]
Substitute \(x = 2\) into the original equation: \[ 2 - [3 - (3 - 2)] = 3(2) - (4 + 2) \] \[ 2 - [3 - 1] = 6 - 6 \] \[ 2 - 2 = 0 \] \[ 0 = 0 \] The equation holds true, so \(x = 2\) is a solution.
Substitute \(x = 4\) into the original equation: \[ 2 - [3 - (3 - 4)] = 3(4) - (4 + 4) \] \[ 2 - [3 - (-1)] = 12 - 8 \] \[ 2 - 4 = 4 \] \[ -2 = 4 \] The equation does not hold true, so \(x = 4\) is not a solution.
(a) \(x = 2\): \(\boxed{\text{Yes}}\)
(b) \(x = 4\): \(\boxed{\text{No}}\)
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