Questions: Evaluate the following integral.
[
int-2^2 e^9 x+7 d x
]
Transcript text: Evaluate the following integral.
\[
\int_{-2}^{2} e^{9 x+7} d x
\]
Solution
Solution Steps
Step 1: Set Up the Integral
We start with the integral we need to evaluate:
\[
\int_{-2}^{2} e^{9x + 7} \, dx
\]
Step 2: Evaluate the Integral
Using the properties of exponents, we can rewrite the integrand:
\[
e^{9x + 7} = e^7 \cdot e^{9x}
\]
Thus, the integral becomes:
\[
e^7 \int_{-2}^{2} e^{9x} \, dx
\]
The integral of \(e^{9x}\) is:
\[
\frac{1}{9} e^{9x}
\]
Evaluating this from \(-2\) to \(2\):
\[
\left[ \frac{1}{9} e^{9x} \right]_{-2}^{2} = \frac{1}{9} e^{18} - \frac{1}{9} e^{-18}
\]
Step 3: Combine Results
Now, we can combine the results:
\[
e^7 \left( \frac{1}{9} e^{18} - \frac{1}{9} e^{-18} \right) = \frac{1}{9} e^7 \left( e^{18} - e^{-18} \right)
\]
This simplifies to:
\[
\frac{1}{9} e^7 \left( e^{18} - e^{-18} \right) = \frac{1}{9} \left( e^{25} - e^{-11} \right)
\]
Final Answer
Thus, the value of the integral is:
\[
\boxed{\frac{1}{9} \left( e^{25} - e^{-11} \right)}
\]