Questions: Participation Activity #8 This is similar to Try It #1 in the OpenStax text. Factor (x(b^2-a)+8(b^2-a)) by pulling out the GCF. Hint Penalty Hint 0.0 View Hint

Participation Activity #8
This is similar to Try It #1 in the OpenStax text.
Factor (x(b^2-a)+8(b^2-a)) by pulling out the GCF.

Hint Penalty
Hint 0.0 View Hint

Transcript text: Participation Activity \#8 This is similar to Try It \#1 in the OpenStax text. Factor $x\left(b^{2}-a\right)+8\left(b^{2}-a\right)$ by pulling out the GCF. \begin{tabular}{|l|l|l|} \hline Hint & Penalty & \\ \hline Hint & 0.0 & View Hint \\ \hline \end{tabular} How Did I Do? Try Another

Solution

Solution Steps

To factor the expression $x(b^2 - a) + 8(b^2 - a)$, we need to identify the greatest common factor (GCF) of the terms. In this case, the GCF is $(b^2 - a)$. We can factor out $(b^2 - a)$ from both terms, which will simplify the expression.

Step 1: Identify the Expression

We start with the expression: \[ x(b^2 - a) + 8(b^2 - a) \]

Step 2: Factor Out the GCF

The greatest common factor (GCF) of the terms is $(b^2 - a)$. We can factor this out: \[ (b^2 - a)(x + 8) \]

Step 3: Simplify the Expression

Rearranging the factored expression gives us: \[ -(a - b^2)(x + 8) \]