$f(x)$ is increasing when $f'(x) > 0$ and decreasing when $f'(x) < 0$.
From the graph of $f'(x)$, we can see that $f'(x) > 0$ on $(0,3)$ and $(6,9)$.
Also, $f'(x) < 0$ on $(3,6)$.
Thus, $f(x)$ is increasing on $(0, 3)$ and $(6, 9)$, and decreasing on $(3, 6)$.
Since $f'(x)$ changes from positive to negative at $x=3$, $f(x)$ has a local maximum at $x=3$.
Since $f'(x)$ changes from negative to positive at $x=6$, $f(x)$ has a local minimum at $x=6$.
$f(x)$ is concave up when $f''(x) > 0$, which means $f'(x)$ is increasing. $f(x)$ is concave down when $f''(x) < 0$, which means $f'(x)$ is decreasing.
$f'(x)$ is increasing on the intervals $(1,5)$ and $(8,9)$. $f'(x)$ is decreasing on the intervals $(0,1)$, $(5,8)$.
Thus, $f(x)$ is concave up on $(1, 5)$ and $(8,9)$, and $f(x)$ is concave down on $(0,1)$ and $(5,8)$. Inflection points occur when the concavity changes. Thus, the inflection points of $f(x)$ are at $x = 1$, $x = 5$ and $x = 8$.
- Increasing: $(0, 3)$ and $(6, 9)$
- Decreasing: $(3, 6)$
- Concave up: $(1, 5)$ and $(8, 9)$
- Concave down: $(0, 1)$ and $(5, 8)$
- Maximum: $x=3$
- Minimum: $x=6$
- Inflection points: $x = 1$, $x = 5$, $x = 8$