The problem involves finding the value of x x x in a parallelogram where the perimeter is given as 32.2. The sides of the parallelogram are labeled with expressions involving x x x.
In the parallelogram URST URST URST:
The perimeter of a parallelogram is the sum of all its sides. Therefore, the equation for the perimeter is: 2(16)+2(3x−8)=32.2 2(16) + 2(3x - 8) = 32.2 2(16)+2(3x−8)=32.2
Simplify the equation to solve for x x x: 32+6x−16=32.2 32 + 6x - 16 = 32.2 32+6x−16=32.2 6x+16=32.2 6x + 16 = 32.2 6x+16=32.2 6x=32.2−16 6x = 32.2 - 16 6x=32.2−16 6x=16.2 6x = 16.2 6x=16.2
Divide both sides by 6 to find x x x: x=16.26 x = \frac{16.2}{6} x=616.2 x=2.7 x = 2.7 x=2.7
The correct equation to set up is: 3x−8+16+3x−8+16=32.2 3x - 8 + 16 + 3x - 8 + 16 = 32.2 3x−8+16+3x−8+16=32.2 The value of x x x is: x=2.7 x = 2.7 x=2.7
So, the correct answers are:
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