To find the values of the piecewise-defined function f(x) f(x) f(x) at specific points, we need to determine which piece of the function applies to each given value of x x x. We then substitute the value of x x x into the appropriate expression to calculate f(x) f(x) f(x).
For x=−1 x = -1 x=−1, since −1≤1 -1 \leq 1 −1≤1, we use the first piece of the function: f(−1)=1−3(−1)=1+3=4 f(-1) = 1 - 3(-1) = 1 + 3 = 4 f(−1)=1−3(−1)=1+3=4
For x=1 x = 1 x=1, since 1≤1 1 \leq 1 1≤1, we again use the first piece of the function: f(1)=1−3(1)=1−3=−2 f(1) = 1 - 3(1) = 1 - 3 = -2 f(1)=1−3(1)=1−3=−2
For x=4 x = 4 x=4, since 1<4<7 1 < 4 < 7 1<4<7, we use the second piece of the function: f(4)=3(4)=12 f(4) = 3(4) = 12 f(4)=3(4)=12
For x=6 x = 6 x=6, since 1<6<7 1 < 6 < 7 1<6<7, we again use the second piece of the function: f(6)=3(6)=18 f(6) = 3(6) = 18 f(6)=3(6)=18
For x=7 x = 7 x=7, since 7≥7 7 \geq 7 7≥7, we use the third piece of the function: f(7)=4(7)+3=28+3=31 f(7) = 4(7) + 3 = 28 + 3 = 31 f(7)=4(7)+3=28+3=31
The values of the function at the specified points are:
Thus, the final answers are: f(−1)=4 \boxed{f(-1) = 4} f(−1)=4 f(1)=−2 \boxed{f(1) = -2} f(1)=−2 f(4)=12 \boxed{f(4) = 12} f(4)=12 f(6)=18 \boxed{f(6) = 18} f(6)=18 f(7)=31 \boxed{f(7) = 31} f(7)=31
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