Questions: Write an equation for a line parallel to y=-3x+5 and passing through the point (2,-9) y=

Write an equation for a line parallel to y=-3x+5 and passing through the point (2,-9)
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Transcript text: Write an equation for a line parallel to $y=-3 x+5$ and passing through the point $(2,-9)$ \[ y= \] $\square$ Question Help: Video
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Solution

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Solution Steps

Step 1: Identify the slope of the given line

The equation of the given line is \( y = -3x + 5 \). The slope of this line is \( -3 \).

Step 2: Use the same slope for the parallel line

Since parallel lines have the same slope, the slope of the desired line is also \( -3 \).

Step 3: Use the point-slope form to find the equation

The point-slope form of a line is \( y - y_1 = m(x - x_1) \), where \( m \) is the slope and \( (x_1, y_1) \) is a point on the line. Substituting the slope \( m = -3 \) and the point \( (2, -9) \):

\[ y - (-9) = -3(x - 2) \]

Step 4: Simplify the equation

Simplify the equation to solve for \( y \):

\[ y + 9 = -3x + 6 \]

\[ y = -3x + 6 - 9 \]

\[ y = -3x - 3 \]

The equation of the line is:

\[ y = -3x - 3 \]

Final Answer

\(\boxed{y = -3x - 3}\)

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