Questions: Name:
CHEM 111 Quiz 3
1) Given the reaction 2 A(g) -> B(g) + C(g)
a) Express the rate of reaction in terms of the change in concentration in terms of the change in concentration of each of the reactants and products.
b) When [C] is increasing at 2.0 mol / L s, how fast is [A] decreasing?
Transcript text: Name: $\qquad$
CHEM 111 Quiz 3
1) Given the reaction $2 A_{(\mathrm{g})} \rightarrow B_{(\mathrm{g})}+\mathrm{C}_{(\mathrm{g})}$
a) Express the rate of reaction in terms of the change in concentration in terms of the change in concentration of each of the reactants and products.
b) When [C] is increasing at $2.0 \mathrm{~mol} / \mathrm{L} \mathrm{s}$, how fast is $[A]$ decreasing?
Solution
Solution Steps
Step 1: Express the Rate of Reaction
For the reaction \(2 A_{(\mathrm{g})} \rightarrow B_{(\mathrm{g})} + \mathrm{C}_{(\mathrm{g})}\), the rate of reaction can be expressed in terms of the change in concentration of each reactant and product.
The rate of reaction \(r\) is given by:
\[
r = -\frac{1}{2} \frac{d[A]}{dt} = \frac{d[B]}{dt} = \frac{d[C]}{dt}
\]
Step 2: Relate the Rate of Change of [C] to [A]
Given that \([C]\) is increasing at \(2.0 \, \mathrm{mol/L \cdot s}\), we can use the rate expression to find how fast \([A]\) is decreasing.
From the rate expression:
\[
r = \frac{d[C]}{dt} = 2.0 \, \mathrm{mol/L \cdot s}
\]
Since:
\[
r = -\frac{1}{2} \frac{d[A]}{dt}
\]
We can set the rates equal to each other:
\[
2.0 = -\frac{1}{2} \frac{d[A]}{dt}
\]
Step 3: Solve for \(\frac{d[A]}{dt}\)
Solving for \(\frac{d[A]}{dt}\):
\[
2.0 = -\frac{1}{2} \frac{d[A]}{dt}
\]
Multiply both sides by \(-2\):
\[
\frac{d[A]}{dt} = -4.0 \, \mathrm{mol/L \cdot s}
\]