Questions: Decide whether the Lewis structure proposed for each molecule is reasonable or not. molecule proposed Lewis structure Is this a reasonable structure? If not, why not? BF3 : F: : F-B-F: Yes, it's a reasonable structure. No, the total number of valence electrons is wrong. The correct number is: No, some atoms have the wrong number of electrons around them. The symbols of the problem atoms are: NH2+ [H-N=H]+ Yes, it's a reasonable structure. No, the total number of valence electrons is wrong. The correct number is: No, some atoms have the wrong number of electrons around them. The symbols of the problem atoms are: BH2+ [H-B-H]+ Yes, it's a reasonable structure. No, the total number of valence electrons is wrong. The correct number is: No, some atoms have the wrong number of electrons around them. The symbols of the problem atoms are: * If two or more atoms have the wrong number of valence electrons around them, just enter the chemical symbol for the atom as many times as necessary. For example, if two oxygen atoms have the wrong number of electrons around them, enter the symbol O twice.

Decide whether the Lewis structure proposed for each molecule is reasonable or not. molecule proposed Lewis structure Is this a reasonable structure? If not, why not? BF3 : F: : F-B-F: Yes, it's a reasonable structure. No, the total number of valence electrons is wrong. The correct number is: No, some atoms have the wrong number of electrons around them. The symbols of the problem atoms are: NH2+ [H-N=H]+ Yes, it's a reasonable structure. No, the total number of valence electrons is wrong. The correct number is: No, some atoms have the wrong number of electrons around them. The symbols of the problem atoms are: BH2+ [H-B-H]+ Yes, it's a reasonable structure. No, the total number of valence electrons is wrong. The correct number is: No, some atoms have the wrong number of electrons around them. The symbols of the problem atoms are: * If two or more atoms have the wrong number of valence electrons around them, just enter the chemical symbol for the atom as many times as necessary. For example, if two oxygen atoms have the wrong number of electrons around them, enter the symbol O twice.
Transcript text: Decide whether the Lewis structure proposed for each molecule is reasonable or not. molecule & proposed Lewis structure & Is this a reasonable structure? If not, why not? $\mathrm{BF}_{3}$ & $\quad: \mathrm{F}:$ $: \ddot{\mathrm{F}}-\mathrm{B}-\ddot{\mathrm{F}:}$ & Yes, it's a reasonable structure. No, the total number of valence electrons is wrong. The correct number is: No, some atoms have the wrong number of electrons around them. The symbols of the problem atoms are: $\mathrm{NH}_{2}^{+}$ & {$[\mathrm{H}-\mathrm{N}=\mathrm{H}]^{+}$} & Yes, it's a reasonable structure. No, the total number of valence electrons is wrong. The correct number is: No, some atoms have the wrong number of electrons around them. The symbols of the problem atoms are: $\mathrm{BH}_{2}^{+}$ & {$[\mathrm{H}-\mathrm{B}-\mathrm{H}]^{+}$} & Yes, it's a reasonable structure. No, the total number of valence electrons is wrong. The correct number is: No, some atoms have the wrong number of electrons around them. The symbols of the problem atoms are: * If two or more atoms have the wrong number of valence electrons around them, just enter the chemical symbol for the atom as many times as necessary. For example, if two oxygen atoms have the wrong number of electrons around them, enter the symbol O twice.
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Solution

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Solution Steps

Step 1: Analyze the Lewis Structure for \(\mathrm{BF}_3\)

  • Valence Electrons Calculation:

    • Boron (B) has 3 valence electrons.
    • Each Fluorine (F) has 7 valence electrons.
    • Total: \(3 + 3 \times 7 = 24\) valence electrons.

  • Structure Evaluation:

    • The proposed structure shows each F with a full octet and B with 6 electrons.
    • Boron is known to be stable with 6 electrons in some compounds.

  • Conclusion:

    • The structure is reasonable as it follows the known behavior of boron.
Step 2: Analyze the Lewis Structure for \(\mathrm{NH}_2^+\)

  • Valence Electrons Calculation:

    • Nitrogen (N) has 5 valence electrons.
    • Each Hydrogen (H) has 1 valence electron.
    • Positive charge indicates loss of 1 electron.
    • Total: \(5 + 2 \times 1 - 1 = 7\) valence electrons.

  • Structure Evaluation:

    • The proposed structure shows N with a double bond to one H and a single bond to the other.
    • This results in N having 6 electrons, which is incorrect.

  • Conclusion:

    • The structure is not reasonable. The problem atom is N.
Step 3: Analyze the Lewis Structure for \(\mathrm{BH}_2^+\)

  • Valence Electrons Calculation:

    • Boron (B) has 3 valence electrons.
    • Each Hydrogen (H) has 1 valence electron.
    • Positive charge indicates loss of 1 electron.
    • Total: \(3 + 2 \times 1 - 1 = 4\) valence electrons.

  • Structure Evaluation:

    • The proposed structure shows B with two single bonds to H.
    • This results in B having 4 electrons, which is typical for boron in cationic species.

  • Conclusion:

    • The structure is reasonable.

Final Answer

  • \(\mathrm{BF}_3\): \(\boxed{\text{Yes, it's a reasonable structure.}}\)
  • \(\mathrm{NH}_2^+\): \(\boxed{\text{No, some atoms have the wrong number of electrons around them. The symbols of the problem atoms are: N}}\)
  • \(\mathrm{BH}_2^+\): \(\boxed{\text{Yes, it's a reasonable structure.}}\)
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