To solve the inequality \(3(4-x) + 3x \leq 16\), we need to:
We start with the inequality: \[ 3(4 - x) + 3x \leq 16 \]
Distribute the 3: \[ 3 \cdot 4 - 3 \cdot x + 3x \leq 16 \] \[ 12 - 3x + 3x \leq 16 \]
Combine the terms involving \( x \): \[ 12 \leq 16 \]
The inequality \( 12 \leq 16 \) is always true. This means that the original inequality holds for all values of \( x \).
\(\boxed{x \in \mathbb{R}}\)
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