To rationalize the denominator of the expression
\[ \frac{\sqrt{13}+17}{\sqrt{12}-8} \]
we multiply both the numerator and the denominator by the conjugate of the denominator, which is \(\sqrt{12}+8\):
\[ \frac{(\sqrt{13}+17)(\sqrt{12}+8)}{(\sqrt{12}-8)(\sqrt{12}+8)} \]
The denominator simplifies as follows:
\[ (\sqrt{12}-8)(\sqrt{12}+8) = (\sqrt{12})^2 - 8^2 = 12 - 64 = -52 \]
Now we expand the numerator:
\[ (\sqrt{13}+17)(\sqrt{12}+8) = \sqrt{13}\cdot\sqrt{12} + 8\sqrt{13} + 17\cdot\sqrt{12} + 17\cdot8 \]
This results in:
\[ \sqrt{156} + 8\sqrt{13} + 17\sqrt{12} + 136 \]
Putting it all together, we have:
\[ \frac{\sqrt{156} + 8\sqrt{13} + 17\sqrt{12} + 136}{-52} \]
The final expression simplifies to:
\[ -\frac{\sqrt{156}}{52} - \frac{8\sqrt{13}}{52} - \frac{17\sqrt{12}}{52} - \frac{136}{52} \]
This can be further simplified to:
\[ -\frac{34}{13} - \frac{17\sqrt{3}}{26} - \frac{2\sqrt{13}}{13} - \frac{\sqrt{39}}{26} \]
Thus, the final simplified result is:
\(\boxed{-\frac{34}{13} - \frac{17\sqrt{3}}{26} - \frac{2\sqrt{13}}{13} - \frac{\sqrt{39}}{26}}\)
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