Questions: Park Street, Scott Street and Oak Street form a triangle. - The angle formed by Oak Street and Park Street measures 62°. - The angle formed by Park Street and Scott Street measures 58°. Which lists the sides of the triangle from least to greatest? Park Street, Oak Street, Scott Street Scott Street, Park Street, Oak Street Scott Street, Oak Street, Park Street Oak Street, Park Street, Scott Street

Park Street, Scott Street and Oak Street form a triangle.
- The angle formed by Oak Street and Park Street measures 62°.
- The angle formed by Park Street and Scott Street measures 58°.

Which lists the sides of the triangle from least to greatest?
Park Street, Oak Street, Scott Street
Scott Street, Park Street, Oak Street
Scott Street, Oak Street, Park Street
Oak Street, Park Street, Scott Street

Transcript text: Park Street, Scott Street and Oak Street form a triangle. - The angle formed by Oak Street and Park Street measures $62^{\circ}$. - The angle formed by Park Street and Scott Street measures $58^{\circ}$. Which lists the sides of the triangle from least to greatest? Park Street, Oak Street, Scott Street Scott Street, Park Street, Oak Street Scott Street, Oak Street, Park Street Oak Street, Park Street, Scott Street

Solution

Solution Steps

Step 1: Determine the third angle of the triangle

The sum of the angles in a triangle is $180^{\circ}$. Given the angles at Oak Street and Park Street ($62^{\circ}$) and Park Street and Scott Street ($58^{\circ}$), the third angle at Scott Street and Oak Street can be calculated as: \[ 180^{\circ} - 62^{\circ} - 58^{\circ} = 60^{\circ}. \]

Step 2: Relate angles to sides

In a triangle, the side opposite the smallest angle is the shortest, and the side opposite the largest angle is the longest. The angles in ascending order are: \[ 58^{\circ}, 60^{\circ}, 62^{\circ}. \] Thus, the sides opposite these angles will also be in ascending order.

Step 3: Identify the sides corresponding to the angles