The given polynomial is \( f(x) = x^3 + x^2 + x + 1 \).
To find the zeros, we need to factor the polynomial. Notice that \( f(x) \) can be factored by grouping: \[ f(x) = x^3 + x^2 + x + 1 = (x^3 + x^2) + (x + 1) \] \[ f(x) = x^2(x + 1) + 1(x + 1) \] \[ f(x) = (x^2 + 1)(x + 1) \]
Set each factor equal to zero and solve for \( x \):
\( x^2 + 1 = 0 \) \[ x^2 = -1 \] \[ x = \pm i \] (where \( i \) is the imaginary unit)
\( x + 1 = 0 \) \[ x = -1 \]
The zeros of the polynomial \( f(x) = x^3 + x^2 + x + 1 \) are \( -1, i, -i \).
Oops, Image-based questions are not yet availableUse Solvely.ai for full features.
Failed. You've reached the daily limit for free usage.Please come back tomorrow or visit Solvely.ai for additional homework help.