Questions: What is 25% of 96?

What is 25% of 96?
Transcript text: What is $25 \%$ of $96 ?$
failed

Solution

failed
failed

Solution Steps

To find 25% of 96, you need to multiply 96 by 0.25. This is because finding a percentage of a number is equivalent to multiplying the number by the percentage expressed as a decimal.

Step 1: Calculate the Percentage

To find \( 25\% \) of \( 96 \), we convert the percentage to a decimal by dividing by \( 100 \): \[ 25\% = \frac{25}{100} = 0.25 \] Next, we multiply \( 96 \) by \( 0.25 \): \[ 96 \times 0.25 = 24 \]

Final Answer

The value of \( 25\% \) of \( 96 \) is \( \boxed{24} \).

Was this solution helpful?
failed
Unhelpful
failed
Helpful

Questions asked by other users

failedAnswered
The value of a car is depreciating at a rate of P'(t). P'(t)=-3,240 e^(-0.09 t) Knowing that the purchase price of the car was 36,000, find a formula for the value of the car after t years. Use this formula to find the value of the car 10 years after it has been purchased.
failedAnswered
A researcher obtains t(20)=2.00 and MD=9 for a repeated-measures study. If the researcher measures effect size using the percentage of variance accounted for, what value will be obtained for r^2 ? 4 / 13 9/20 4/24 9/29
failedAnswered
Adam Incorporated makes specialized garden figurines. Its monthly total is 760 when it charges 20 for each figurine. One month, the firm tried lowering its price to 19, and its total sales revenue that month dropped to 760. On the basis of this data. What is the price elasticity of demand for Adam Incorporated's product? Note: Round your answer to 2 decimal places.
failedAnswered
Motion Sensor A cart of mass m is pulled along a level dynamics track as shown above. A force sensor is attached to the cart with a string and used to measure the horizontal force exerted on the cart to the right. A motion sensor is used to measure the acceleration of the cart with the positive direction toward the right. Friction is not negligible. a. On the dot below, which represents the cart, draw and label the forces (not components) that act on the cart. Each force must be represented by a distinct arrow starting on, and pointing away from, the dot. A student pulls the force sensor with a constant force, and the cart accelerates. This is repeated for several trials, with a different constant force used for each trial. The data are recorded in the table below. Trial 1 2 3 4 5 Force sensor reading (N) 0.32 0.38 0.44 0.50 0.60 Acceleration (m / s^2) 0.12 0.22 0.33 0.50 0.70 b. i. On the grid below, plot data points for the acceleration of the cart as a function of the force sensor reading. Clearly scale all axes. Draw a straight line that best represents the data.
failedAnswered
The sum of forty and y