Questions: Complex Structures: Mastery Test 4. Drag the tiles to the correct boxes to complete the parts of chromium(IV) oxide Cr O₂ Cr O₄ Cr O₃ Cr O

Solution Steps

Chromium(IV) oxide refers to a compound where chromium has an oxidation state of +4. The chemical formula for chromium(IV) oxide can be determined by balancing the charges of chromium and oxygen.

Chromium in the +4 oxidation state is denoted as \( \text{Cr}^{4+} \). Oxygen typically has an oxidation state of -2. To balance the charges, we need two oxygen atoms to balance one chromium atom: \[ \text{Cr}^{4+} + 2 \times \text{O}^{2-} \rightarrow \text{CrO}_2 \]

From the given options, the correct formula for chromium(IV) oxide is \( \text{CrO}_2 \).

Final Answer