Questions: Using VSEPR theory, predict the electron group geometry, molecular shape, and the bond angles in a molecule that contains 5 electron groups (2 bonds and 3 lone pair electrons).
trigonal bipyramidal, trigonal bipyramidal, 90° and 120°
trigonal bipyramidal, trigonal bipyramidal, 180°
trigonal bipyramidal, linear, 180°
Transcript text: Using VSEPR theory, predict the electron group geometry, molecular shape, and the bond angles in a molecule that contains 5 electron groups (2 bonds and 3 lone pair electrons). (Outcome \# 12) (DOK 2) (Paired item 1)
trigonal bipyramidal, trigonal bipyramidal, $90^{\circ}$ and $120^{\circ}$
trigonal bipyramidal, trigonal bipyramidal, $180^{\circ}$
trigonal bipyramidal, linear, $180^{\circ}$
Solution
Solution Steps
Step 1: Determine the Electron Group Geometry
According to VSEPR (Valence Shell Electron Pair Repulsion) theory, the electron group geometry is determined by the total number of electron groups around the central atom. In this case, there are 5 electron groups (2 bonds and 3 lone pairs). The electron group geometry for 5 electron groups is trigonal bipyramidal.
Step 2: Determine the Molecular Shape
The molecular shape is determined by the arrangement of the atoms (bonds) around the central atom, considering the lone pairs. With 2 bonds and 3 lone pairs, the molecular shape is linear. This is because the lone pairs occupy the equatorial positions in the trigonal bipyramidal geometry, leaving the two bonded atoms in a linear arrangement.
Step 3: Determine the Bond Angles
In a linear molecular shape derived from a trigonal bipyramidal electron group geometry, the bond angle between the two bonded atoms is \(180^\circ\).