Questions: G2-T1
UNIT 6
LESSON 6
Equations inequalities
Systems of Equations
Systems of Equations Quick Check
Solve the system of equations.
y = -x + 2
3x + 3y = 6
Which best describes the solution?
(1 point)
One solution at (0,2)
There are infinitely many solutions.
There are no solutions.
One solution at (2/3, 8/3)
Transcript text: $\mathrm{G} 2-\mathrm{T} 1$
UNIT 6
IESSON 6
Equations 8 inequalities
Systems of Equations
Systems of Equations Quick Che
Solve the system of equations.
\[
\begin{array}{l}
y=-x+2 \\
3 x+3 y=6
\end{array}
\]
Which best describes the solution?
(1 point)
One solution at $(0,2)$
There are infinitely many solutions.
There are no solutions.
One solution at $\left(\frac{2}{3}, \frac{8}{3}\right)$
Solution
Solution Steps
To solve the system of equations, we can use the substitution method. First, substitute the expression for \( y \) from the first equation into the second equation. Then, solve for \( x \). Once \( x \) is found, substitute it back into the first equation to find \( y \). Finally, check if the solution satisfies both equations to determine the correct description of the solution.
Step 1: Substitute \( y \) in the Second Equation
We start with the system of equations:
\[
\begin{align_}
y &= -x + 2 \quad (1) \\
3x + 3y &= 6 \quad (2)
\end{align_}
\]
Substituting equation (1) into equation (2):
\[
3x + 3(-x + 2) = 6
\]
Step 2: Simplify the Equation
Now, simplify the equation:
\[
3x - 3x + 6 = 6
\]
This simplifies to:
\[
6 = 6
\]
This is a true statement, indicating that the equations are dependent.
Step 3: Determine the Nature of the Solution
Since the equations are dependent, there are infinitely many solutions. The solutions can be expressed in terms of \( x \):
\[
y = -x + 2
\]
This means for any value of \( x \), there exists a corresponding \( y \).
Final Answer
The system of equations has infinitely many solutions. Thus, the answer is:
\[
\boxed{\text{There are infinitely many solutions.}}
\]