Questions: Calculate the pH of the following solutions: 2.8 M KOH Express your answer using two decimal places. pH= 0.065 M NaOH Express your answer using two decimal places. pH=

Calculate the pH of the following solutions: 2.8 M KOH Express your answer using two decimal places. pH= 0.065 M NaOH Express your answer using two decimal places. pH=
Transcript text: Part C\n\nCalculate the pH of the following solutions:\n2.8 M KOH\n\nExpress your answer using two decimal places.\n$\\mathrm{pH}=$ $\\square$\nSubmit\nRequest Answer\n\nPart D\n0.065 M NaOH\n\nExpress your answer using two decimal places.\n$\\mathrm{pH}=$ $\\square$\nSubmit\nRequest Answer
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Solution

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Schritt 1: Bestimmen der Konzentration von OH\(^-\) Ionen

Für eine Lösung von KOH oder NaOH dissoziiert das Hydroxidion vollständig. Daher ist die Konzentration von OH\(^-\) Ionen gleich der Konzentration der Lösung.

Für 2.8 M KOH: \[ [\text{OH}^-] = 2.8 \, \text{M} \]

Für 0.065 M NaOH: \[ [\text{OH}^-] = 0.065 \, \text{M} \]

Schritt 2: Berechnen des pOH

Der pOH wird berechnet mit der Formel: \[ \text{pOH} = -\log[\text{OH}^-] \]

Für 2.8 M KOH: \[ \text{pOH} = -\log(2.8) = -0.4472 \]

Für 0.065 M NaOH: \[ \text{pOH} = -\log(0.065) = 1.1871 \]

Schritt 3: Berechnen des pH

Der pH-Wert wird berechnet mit der Formel: \[ \text{pH} = 14 - \text{pOH} \]

Für 2.8 M KOH: \[ \text{pH} = 14 - (-0.4472) = 14.4472 \approx 14.45 \]

Für 0.065 M NaOH: \[ \text{pH} = 14 - 1.1871 = 12.8129 \approx 12.81 \]

Endgültige Antwort

\[ \boxed{\text{pH} = 14.45} \] \[ \boxed{\text{pH} = 12.81} \]

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