Questions: On a number line, point D is at -3, and point E is at 6. The point F lies on DE. The ratio of DF to FE is 2:3. Where does point F lie on the number line?
Point F is at on the number line.
Transcript text: On a number line, point D is at -3 , and point E is at 6 . The point F lies on $\overline{\mathrm{DE}}$. The ratio of $D F$ to $F E$ is $2: 3$. Where does point F lie on the number line?
Point $F$ is at $\square$ on the number line.
Solution
Solution Steps
To find the position of point F on the number line, we need to divide the segment DE into parts that reflect the given ratio of DF to FE, which is 2:3. This means the entire segment DE is divided into 5 equal parts, with DF consisting of 2 parts and FE consisting of 3 parts. We can calculate the length of each part and then determine the position of F by adding the length of DF to the position of D.
Step 1: Determine the Total Length of Segment DE
The points D and E are located at \(-3\) and \(6\) on the number line, respectively. The total length of segment DE is calculated as:
\[
\text{Length of DE} = E - D = 6 - (-3) = 9
\]
Step 2: Divide the Segment DE According to the Given Ratio
The ratio of \(DF\) to \(FE\) is \(2:3\). This means the segment DE is divided into \(2 + 3 = 5\) equal parts. Each part has a length of:
\[
\text{Part length} = \frac{\text{Length of DE}}{\text{Total parts}} = \frac{9}{5} = 1.8
\]
Step 3: Calculate the Position of Point F
Point F is located such that \(DF\) consists of 2 parts. Therefore, the position of F is:
\[
F = D + 2 \times \text{Part length} = -3 + 2 \times 1.8 = -3 + 3.6 = 0.6
\]
Final Answer
The position of point F on the number line is \(\boxed{0.6}\).