Questions: Fill in the blanks. (Enter an exact positive number as an integer, fraction, or decimal.) In a normal distribution, x=3 and z=-1.21. This tells you that x=3 is standard deviations to the of the mean.

Fill in the blanks. (Enter an exact positive number as an integer, fraction, or decimal.)
In a normal distribution, x=3 and z=-1.21. This tells you that x=3 is  standard deviations to the  of the mean.
Transcript text: Fill in the blanks. (Enter an exact positive number as an integer, fraction, or decimal.) In a normal distribution, $x=3$ and $z=-1.21$. This tells you that $x=3$ is $\square$ standard deviations to the $\square$ of the mean.
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Solution

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Solution Steps

Step 1: Understanding the Z-Score

In a normal distribution, the z-score is calculated using the formula:

\[ z = \frac{x - \mu}{\sigma} \]

where:

  • \( z \) is the z-score,
  • \( x \) is the value in question,
  • \( \mu \) is the mean of the distribution,
  • \( \sigma \) is the standard deviation.
Step 2: Rearranging the Formula

Given that \( x = 3 \) and \( z = -1.21 \), we can rearrange the formula to express the relationship between \( x \), the mean \( \mu \), and the standard deviation \( \sigma \):

\[ 3 = \mu - 1.21 \sigma \]

This indicates that \( x = 3 \) is located \( 1.21 \) standard deviations to the left of the mean.

Step 3: Conclusion

Since the z-score is negative, it confirms that \( x = 3 \) is indeed \( 1.21 \) standard deviations below the mean.

Final Answer

\(\boxed{1.21}\) standard deviations to the left of the mean.

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