Transcript text: Solve for $v$.
\[
-12 v-9=4 v^{2}
\]
Solution
Solution Steps
Step 1: Rearranging the Equation
We start with the equation:
\[
-12v - 9 = 4v^{2}
\]
Rearranging it to standard polynomial form gives:
\[
4v^{2} + 12v + 9 = 0
\]
Step 2: Factoring the Polynomial
Next, we factor the polynomial \(4v^{2} + 12v + 9\). The factorization results in:
\[
(2v + 3)^{2} = 0
\]
Step 3: Solving for \(v\)
To find the solutions for \(v\), we set the factored expression equal to zero:
\[
(2v + 3)^{2} = 0
\]
Taking the square root of both sides, we have:
\[
2v + 3 = 0
\]
Solving for \(v\) gives:
\[
v = -\frac{3}{2}
\]