To find the probability \( P(z \geq -2.5) \), we can express it using the cumulative distribution function \( \Phi \):
\[ P(z \geq -2.5) = 1 - P(z < -2.5) = 1 - \Phi(-2.5) \]
Using the properties of the standard normal distribution, we have:
\[ P(z \geq -2.5) = \Phi(\infty) - \Phi(-2.5) = 0.9938 \]
Thus, the result for part d is:
\[ \boxed{P(z \geq -2.5) = 0.9938} \]
To find the probability \( P(-3 < z \leq 0) \), we can express it as:
\[ P(-3 < z \leq 0) = P(z \leq 0) - P(z \leq -3) = \Phi(0) - \Phi(-3) \]
Using the cumulative distribution function values, we have:
\[ P(-3 < z \leq 0) = \Phi(0) - \Phi(-3) = 0.4987 \]
Thus, the result for part e is:
\[ \boxed{P(-3 < z \leq 0) = 0.4987} \]
The answers to the questions are:
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