Questions: What is the molarity of a solution containing 8.3 g of NaOH in 600 mL of NaOH solution? Express your answer to two significant figures and include the appropriate units. Molarity = Value Units

Solution Steps

First, we need to determine the molar mass of NaOH. The molar mass is the sum of the atomic masses of sodium (Na), oxygen (O), and hydrogen (H).

\[ \text{Molar mass of NaOH} = 22.99 \, (\text{Na}) + 15.999 \, (\text{O}) + 1.008 \, (\text{H}) = 39.997 \, \text{g/mol} \]

Next, we convert the given mass of NaOH to moles using the molar mass.

\[ \text{Moles of NaOH} = \frac{8.3 \, \text{g}}{39.997 \, \text{g/mol}} = 0.2075 \, \text{mol} \]

The volume of the solution is given in milliliters. We need to convert this to liters.

\[ 600 \, \text{mL} = 0.600 \, \text{L} \]

Molarity (M) is defined as the number of moles of solute per liter of solution.

\[ \text{Molarity} = \frac{\text{Moles of NaOH}}{\text{Volume of solution in L}} = \frac{0.2075 \, \text{mol}}{0.600 \, \text{L}} = 0.3458 \, \text{M} \]

Finally, we round the molarity to two significant figures.

\[ \text{Molarity} \approx 0.35 \, \text{M} \]

Final Answer