Questions: Final Exam Find the area. Area of square=[?] in^2 Area of triangle= square in^2 Remember: Asquare=bh 18 in Area of Figure = square in^2

Transcript text: Final Exam Find the area. Area of $\square=[?] \mathrm{in}^{2}$ Area of $\Delta=$ $\square$ $\mathrm{in}^{2}$ Remember: $A_{\square}=b h$ 18 in Area of Figure = $\square$ $i n^{2}$

Solution

Solution Steps

Step 1: Calculate the area of the rectangle

The area of a rectangle is given by the formula $A_{\square} = bh$, where $b$ is the base and $h$ is the height. In this case, the base is 18 inches and the height is 15 inches.

$A_{\square} = 18 \text{ in} \times 15 \text{ in} = 270 \text{ in}^2$

Step 2: Calculate the area of the triangle

The area of a triangle is given by the formula $A_{\triangle} = \frac{1}{2}bh$, where $b$ is the base and $h$ is the height. In this case, the base is 12 inches and the height is 9 inches.

$A_{\triangle} = \frac{1}{2} \times 12 \text{ in} \times 9 \text{ in} = 54 \text{ in}^2$

Step 3: Calculate the total area

The total area of the figure is the sum of the area of the rectangle and the area of the triangle.

Total Area = $A_{\square} + A_{\triangle} = 270 \text{ in}^2 + 54 \text{ in}^2 = 324 \text{ in}^2$