Questions: We have a deck of 10 cards numbered from 1 to 10. Some are grey and some are white. The cards numbered 1,2,3,5,6,8, and 9 are grey. The cards numbered 4,7, and 10 are white. A card is drawn at random. Let X be the event that the drawn card is grey, and let P(X) be the probability of X. Let not X be the event that the drawn card is not grey, and let P (not X) be the probability of not X. (a) For each event in the table, check the outcome(s) that are contained in the event. Then, in the last column, enter the probability of the event. Event Outcomes Probability - 1 2 3 4 5 6 7 8 9 10 - X P(X)= - not X P(not X)= (b) Subtract. 1-P(not X)=

We have a deck of 10 cards numbered from 1 to 10. Some are grey and some are white.

The cards numbered 1,2,3,5,6,8, and 9 are grey. The cards numbered 4,7, and 10 are white.

A card is drawn at random. Let X be the event that the drawn card is grey, and let P(X) be the probability of X. Let not X be the event that the drawn card is not grey, and let P (not X) be the probability of not X. (a) For each event in the table, check the outcome(s) that are contained in the event. Then, in the last column, enter the probability of the event. Event  Outcomes  Probability -  1  2  3  4  5  6  7  8  9  10  - X            P(X)= - not X            P(not X)= (b) Subtract. 1-P(not X)=
Transcript text: We have a deck of 10 cards numbered from 1 to 10. Some are grey and some are white. The cards numbered $1,2,3,5,6,8$, and 9 are grey. The cards numbered 4,7, and 10 are white. A card is drawn at random. Let $X$ be the event that the drawn card is grey, and let $P(X)$ be the probability of $X$. Let not $X$ be the event that the drawn card is not grey, and let $P$ (not $X$) be the probability of not $X$. (a) For each event in the table, check the outcome(s) that are contained in the event. Then, in the last column, enter the probability of the event. \begin{tabular}{|c|c|c|c|c|c|c|c|c|c|c|c|} \hline \multirow{2}{*}{ Event } & \multicolumn{7}{|c|}{ Outcomes } & Probability \\ \hline & 1 & 2 & 3 & 4 & 5 & 6 & 7 & 8 & 9 & 10 & \\ \hline$X$ & $\square$ & $\square$ & $\square$ & $\square$ & $\square$ & $\square$ & $\square$ & $\square$ & $\square$ & $\square$ & $P(X)=\square$ \\ \hline $\operatorname{not} X$ & $\square$ & $\square$ & $\square$ & $\square$ & $\square$ & $\square$ & $\square$ & $\square$ & $\square$ & $\square$ & $P(\operatorname{not} X)=\square$ \\ \hline \end{tabular} (b) Subtract. \[ 1-P(\operatorname{not} X)= \]
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Solution

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Solution Steps

Step 1: Identify the Total Number of Items (N)

The total number of items in the set is 10.

Step 2: Identify the Number of Items with the Specified Attribute (M)

The number of items with the attribute 'grey' is 7.

Step 3: Calculate the Probability (P)

The probability of drawing an item with the attribute 'grey' is calculated as follows: \[P = \frac{M}{N} = \frac{7}{10} = 0.7\]

Step 4: Calculate the Probability of Not Drawing an Item with the Specified Attribute (P(not X))

The probability of not drawing an item with the attribute 'grey' is calculated as follows: \[P(\text{not } X) = 1 - P(X) = 1 - 0.7 = 0.3\]

Final Answer:

The probability of drawing an item with the attribute 'grey' is 0.7, while the probability of not drawing an item with the attribute 'grey' is 0.3.

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