Questions: Solve the linear equation for (y).
[5x-4y=-100]
Solve the following for (y): (fracx4+fracy5=1)
[y=
]
Solve the equation for (h).
[frac8w=frac7m+frac3h]
Transcript text: Solve the linear equation for $y$.
\[
5x-4y=-100
\]
Solve the following for $\mathrm{y}: \frac{x}{4}+\frac{y}{5}=1$
\[
y=
\]
Solve the equation for $h$.
\[
\frac{8}{w}=\frac{7}{m}+\frac{3}{h}
\]
Solution
Solution Steps
Step 1: Solve the linear equation for \( y \) in \( 5x - 4y = -100 \)
Start with the equation:
\[
5x - 4y = -100
\]
Subtract \( 5x \) from both sides:
\[
-4y = -100 - 5x
\]
Divide both sides by \( -4 \):
\[
y = \frac{-100 - 5x}{-4}
\]
Simplify the equation:
\[
y = \frac{100 + 5x}{4}
\]
Step 2: Solve for \( y \) in \( \frac{x}{4} + \frac{y}{5} = 1 \)
Start with the equation:
\[
\frac{x}{4} + \frac{y}{5} = 1
\]
Subtract \( \frac{x}{4} \) from both sides:
\[
\frac{y}{5} = 1 - \frac{x}{4}
\]
Multiply both sides by \( 5 \):
\[
y = 5 \left(1 - \frac{x}{4}\right)
\]
Simplify the equation:
\[
y = 5 - \frac{5x}{4}
\]
Step 3: Solve the equation for \( h \) in \( \frac{8}{w} = \frac{7}{m} + \frac{3}{h} \)
Start with the equation:
\[
\frac{8}{w} = \frac{7}{m} + \frac{3}{h}
\]
Subtract \( \frac{7}{m} \) from both sides:
\[
\frac{8}{w} - \frac{7}{m} = \frac{3}{h}
\]
Take the reciprocal of both sides:
\[
h = \frac{3}{\frac{8}{w} - \frac{7}{m}}
\]
Simplify the denominator:
\[
h = \frac{3}{\frac{8m - 7w}{wm}}
\]
Multiply by the reciprocal:
\[
h = \frac{3wm}{8m - 7w}
\]
Final Answer
For Question 28: \( \boxed{y = \frac{100 + 5x}{4}} \)