Questions: Write the equilibrium constant expression, (K), for the following reaction. Please enter the compounds in the order given in the reaction. If either the numerator or denominator is blank, please enter 1
((mathrmCH3)3 mathrm~N(mathrmaq)+mathrmH2 mathrmO(mathrml) rightleftharpoons(mathrmCH3)3 mathrmNH^+(mathrmaq)+mathrmOH^-(mathrmaq))
(K=)
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Transcript text: Write the equilibrium constant expression, $K$, for the following reaction. Please enter the compounds in the order given in the reaction. If either the numerator or denominator is blank, please enter 1
\[
\left(\mathrm{CH}_{3}\right)_{3} \mathrm{~N}(\mathrm{aq})+\mathrm{H}_{2} \mathrm{O}(\mathrm{l}) \rightleftharpoons\left(\mathrm{CH}_{3}\right)_{3} \mathrm{NH}^{+}(\mathrm{aq})+\mathrm{OH}^{-}(\mathrm{aq})
\]
$\square$
\[
K=
\]
$\square$
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Solution
Solution Steps
Step 1: Identify the Reactants and Products
The given reaction is:
\[
\left(\mathrm{CH}_{3}\right)_{3} \mathrm{~N}(\mathrm{aq})+\mathrm{H}_{2} \mathrm{O}(\mathrm{l}) \rightleftharpoons\left(\mathrm{CH}_{3}\right)_{3} \mathrm{NH}^{+}(\mathrm{aq})+\mathrm{OH}^{-}(\mathrm{aq})
\]
Step 2: Write the Equilibrium Constant Expression
The equilibrium constant expression, \( K \), for a reaction is given by the ratio of the product of the concentrations of the products to the product of the concentrations of the reactants, each raised to the power of their respective coefficients in the balanced equation.
For the reaction:
\[
\left(\mathrm{CH}_{3}\right)_{3} \mathrm{~N}(\mathrm{aq})+\mathrm{H}_{2} \mathrm{O}(\mathrm{l}) \rightleftharpoons\left(\mathrm{CH}_{3}\right)_{3} \mathrm{NH}^{+}(\mathrm{aq})+\mathrm{OH}^{-}(\mathrm{aq})
\]
The equilibrium constant expression is:
\[
K = \frac{[\left(\mathrm{CH}_{3}\right)_{3} \mathrm{NH}^{+}][\mathrm{OH}^{-}]}{[\left(\mathrm{CH}_{3}\right)_{3} \mathrm{~N}]}
\]
Step 3: Simplify the Expression
Since \(\mathrm{H}_{2} \mathrm{O}(\mathrm{l})\) is a pure liquid, its concentration is constant and does not appear in the equilibrium constant expression.