Questions: Coronary bypass surgery: A healthcare research agency reported that 46% of people who had coronary bypass surgery in 2008 were over the age of 65. Twelve coronary bypass patients are sampled.
Part 1 of 2
(a) What is the mean number of people over the age of 65 in a sample of 12 coronary bypass patients? Round the answer to two decimal places.
The mean number of people over the age of 65 is 1.
Part 2 of 2
(b) What is the standard deviation of the number of people over the age of 65 in a sample of 12 coronary bypass patients? Round the answer to four decimal places.
The standard deviation of the number of people over the age of 65 is .
Transcript text: Coronary bypass surgery: A healthcare research agency reported that $46 \%$ of people who had coronary bypass surgery in 2008 were over the age of 65. Twelve coronary bypass patients are sampled.
Part 1 of 2
(a) What is the mean number of people over the age of 65 in a sample of 12 coronary bypass patients? Round the answer to two decimal places.
The mean number of people over the age of 65 is $\square$ 1.
Part 2 of 2
(b) What is the standard deviation of the number of people over the age of 65 in a sample of 12 coronary bypass patients? Round the answer to four decimal places.
The standard deviation of the number of people over the age of 65 is $\square$ .
Solution
Solution Steps
Step 1: Calculate the Mean
To find the mean number of people over the age of 65 in a sample of 12 coronary bypass patients, we use the formula for the mean of a binomial distribution:
\[
\mu = n \cdot p
\]
where:
\( n = 12 \) (the number of trials),
\( p = 0.46 \) (the probability of success).
Calculating this gives:
\[
\mu = 12 \cdot 0.46 = 5.52
\]
Thus, the mean number of people over the age of 65 is \( 5.52 \).
Step 2: Calculate the Standard Deviation
Next, we calculate the standard deviation using the formula:
\[
\sigma = \sqrt{n \cdot p \cdot q}
\]
where:
\( q = 1 - p = 0.54 \) (the probability of failure).
Calculating the variance first:
\[
\sigma^2 = n \cdot p \cdot q = 12 \cdot 0.46 \cdot 0.54 = 2.9808
\]
Now, taking the square root to find the standard deviation:
\[
\sigma = \sqrt{2.9808} \approx 1.7265
\]
Thus, the standard deviation of the number of people over the age of 65 is \( 1.7265 \).
Final Answer
The mean number of people over the age of 65 is \( \boxed{5.52} \) and the standard deviation is \( \boxed{1.7265} \).