Questions: Carry out each calculation and give the answers using the proper number of significant figures. Part 1 of 2 20.50 × 4.6= Part 2 of 2 0.707 / 18324=

Carry out each calculation and give the answers using the proper number of significant figures. Part 1 of 2 20.50 × 4.6= Part 2 of 2 0.707 / 18324=
Transcript text: Student Portal | Main CHM-101 Topic 1: Chemistry ALEKS - Kristina Seaver - Ho www-awu.aleks.com/alekscgi/x/lsl.exe/1o_u-IgNsIkr7j8P3jH-Iv-O2hl7zh5A8CnG03PBGuXr8iCPa7ZMmym Homework 1 Question 4 of 17 (1 point) | Question Attempt: 1 of 3 $\checkmark 1$ $\checkmark 2$ $\checkmark 3$ 4 5 6 7 8 Carry out each calculation and give the answers using the proper number of significant figures. Part 1 of 2 \[ 20.50 \times 4.6= \] $\square$ Part 2 of 2 \[ \frac{0.707}{18324}= \] $\square$ Check - 2024 Mc Search or type URL $\%$ 5 \& 7 1 2 $\#$ 3 \$ 4 6 R T Y U A S D F G
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Solution

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Solution Steps

Step 1: Multiplication with Significant Figures

First, we need to multiply \(20.50\) by \(4.6\).

  • \(20.50\) has 4 significant figures.
  • \(4.6\) has 2 significant figures.

The result should be rounded to the least number of significant figures, which is 2.

\[ 20.50 \times 4.6 = 94.30 \]

Rounding to 2 significant figures:

\[ 94.30 \approx 94 \]

Step 2: Division with Significant Figures

Next, we need to divide \(0.707\) by \(18324\).

  • \(0.707\) has 3 significant figures.
  • \(18324\) has 5 significant figures.

The result should be rounded to the least number of significant figures, which is 3.

\[ \frac{0.707}{18324} \approx 3.858 \times 10^{-5} \]

Rounding to 3 significant figures:

\[ 3.858 \times 10^{-5} \approx 3.86 \times 10^{-5} \]

Final Answer

\[ \boxed{94} \] \[ \boxed{3.86 \times 10^{-5}} \]

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