Questions: 2. Leron claims that you cannot graph y=0.5x because there is no y-intercept. Is he correct? Why or why not?

2. Leron claims that you cannot graph y=0.5x because there is no y-intercept. Is he correct? Why or why not?
Transcript text: 2. Leron claims that you cannot graph $y=0.5 x$ because there is no $y$-intercept. is he correct? Why or why not? $\qquad$ $\qquad$ $\qquad$ $\qquad$ $\qquad$
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Solution

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Solution Steps

Step 1: Identify the equation and its form

The given equation is \( y = 0.5x \). This is a linear equation in the slope-intercept form \( y = mx + b \), where \( m \) is the slope and \( b \) is the \( y \)-intercept.

Step 2: Determine the slope and \( y \)-intercept

In the equation \( y = 0.5x \), the slope \( m \) is \( 0.5 \), and the \( y \)-intercept \( b \) is \( 0 \) (since there is no constant term added to \( 0.5x \)).

Step 3: Analyze Leron's claim

Leron claims that the graph of \( y = 0.5x \) cannot be drawn because there is no \( y \)-intercept. However, the \( y \)-intercept is \( 0 \), which means the line passes through the origin \((0, 0)\). Therefore, the graph can indeed be drawn.

Step 4: Conclusion

Leron is incorrect. The graph of \( y = 0.5x \) can be drawn, and it passes through the origin \((0, 0)\).

Final Answer

Leron is incorrect. The graph of \( y = 0.5x \) can be drawn, and it passes through the origin \((0, 0)\).

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