Carboxylic acids, such as acetic acid (CH3COOH\mathrm{CH}_3\mathrm{COOH}CH3COOH), dissociate in water to form a carboxylate ion (CH3COO−\mathrm{CH}_3\mathrm{COO}^-CH3COO−) and a hydronium ion (H3O+\mathrm{H}_3\mathrm{O}^+H3O+). This process involves the transfer of a proton (H+\mathrm{H}^+H+) from the carboxylic acid to a water molecule.
Let's analyze each given equation to determine which one correctly represents the dissociation of a carboxylic acid in water:
CH3COOH⇌CH3COO−+H+\mathrm{CH}_3\mathrm{COOH} \rightleftharpoons \mathrm{CH}_3\mathrm{COO}^- + \mathrm{H}^+CH3COOH⇌CH3COO−+H+
CH3COOH+H2O⇌CH3COO−+H3O+\mathrm{CH}_3\mathrm{COOH} + \mathrm{H}_2\mathrm{O} \rightleftharpoons \mathrm{CH}_3\mathrm{COO}^- + \mathrm{H}_3\mathrm{O}^+CH3COOH+H2O⇌CH3COO−+H3O+
CH3COOH+H2O⇌CH3CHCOOH2++OH−\mathrm{CH}_3\mathrm{COOH} + \mathrm{H}_2\mathrm{O} \rightleftharpoons \mathrm{CH}_3\mathrm{CHCOOH}_2^+ + \mathrm{OH}^-CH3COOH+H2O⇌CH3CHCOOH2++OH−
CH3COOH+H3O+⇌CH3COOH2++H2O\mathrm{CH}_3\mathrm{COOH} + \mathrm{H}_3\mathrm{O}^+ \rightleftharpoons \mathrm{CH}_3\mathrm{COOH}_2^+ + \mathrm{H}_2\mathrm{O}CH3COOH+H3O+⇌CH3COOH2++H2O
CH3COOH+2H2O⇌CH3COO2−+2H3O+\mathrm{CH}_3\mathrm{COOH} + 2 \mathrm{H}_2\mathrm{O} \rightleftharpoons \mathrm{CH}_3\mathrm{COO}^{2-} + 2 \mathrm{H}_3\mathrm{O}^+CH3COOH+2H2O⇌CH3COO2−+2H3O+
The correct equation representing the dissociation of a carboxylic acid in water is:
CH3COOH+H2O⇌CH3COO−+H3O+ \boxed{\mathrm{CH}_3\mathrm{COOH} + \mathrm{H}_2\mathrm{O} \rightleftharpoons \mathrm{CH}_3\mathrm{COO}^- + \mathrm{H}_3\mathrm{O}^+} CH3COOH+H2O⇌CH3COO−+H3O+
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