Questions: Which equation correctly represents the dissociation of a carboxylic acid in water? CH3COOH ⇌ CH3COO^- + H^+ CH3COOH + H2O ⇌ CH3COO^- + H3O^+ CH3COOH + H2O ⇌ CH3CHCOOH2^+ + OH^- CH3COOH + H3O^+ ⇌ CH3COOH2^+ + H2O CH3COOH + 2 H2O ⇌ CH3COO^2- + 2 H3O^+

Which equation correctly represents the dissociation of a carboxylic acid in water?
CH3COOH ⇌ CH3COO^- + H^+
CH3COOH + H2O ⇌ CH3COO^- + H3O^+
CH3COOH + H2O ⇌ CH3CHCOOH2^+ + OH^-
CH3COOH + H3O^+ ⇌ CH3COOH2^+ + H2O
CH3COOH + 2 H2O ⇌ CH3COO^2- + 2 H3O^+
Transcript text: Which equation correctly represents the dissociation of a carboxylic acid in water? $\mathrm{CH}_{3} \mathrm{COOH} \rightleftharpoons \mathrm{CH}_{3} \mathrm{COO}^{-}+\mathrm{H}^{+}$ $\mathrm{CH}_{3} \mathrm{COOH}+\mathrm{H}_{2} \mathrm{O} \rightleftharpoons \mathrm{CH}_{3} \mathrm{COO}^{-}+\mathrm{H}_{3} \mathrm{O}^{+}$ $\mathrm{CH}_{3} \mathrm{COOH}+\mathrm{H}_{2} \mathrm{O} \rightleftharpoons \mathrm{CH}_{3} \mathrm{CHCOOH}_{2}^{+}+\mathrm{OH}^{-}$ $\mathrm{CH}_{3} \mathrm{COOH}+\mathrm{H}_{3} \mathrm{O}^{+} \rightleftharpoons \mathrm{CH}_{3} \mathrm{COOH}_{2}^{+}+\mathrm{H}_{2} \mathrm{O}$ $\mathrm{CH}_{3} \mathrm{COOH}+2 \mathrm{H}_{2} \mathrm{O} \rightleftharpoons \mathrm{CH}_{3} \mathrm{COO}^{2-}+2 \mathrm{H}_{3} \mathrm{O}^{+}$
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Solution

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Solution Steps

Step 1: Understanding Carboxylic Acid Dissociation

Carboxylic acids, such as acetic acid (CH3COOH\mathrm{CH}_3\mathrm{COOH}), dissociate in water to form a carboxylate ion (CH3COO\mathrm{CH}_3\mathrm{COO}^-) and a hydronium ion (H3O+\mathrm{H}_3\mathrm{O}^+). This process involves the transfer of a proton (H+\mathrm{H}^+) from the carboxylic acid to a water molecule.

Step 2: Analyzing the Given Equations

Let's analyze each given equation to determine which one correctly represents the dissociation of a carboxylic acid in water:

  1. CH3COOHCH3COO+H+\mathrm{CH}_3\mathrm{COOH} \rightleftharpoons \mathrm{CH}_3\mathrm{COO}^- + \mathrm{H}^+

    • This equation shows the dissociation of acetic acid into acetate and a proton, but it does not involve water explicitly.
  2. CH3COOH+H2OCH3COO+H3O+\mathrm{CH}_3\mathrm{COOH} + \mathrm{H}_2\mathrm{O} \rightleftharpoons \mathrm{CH}_3\mathrm{COO}^- + \mathrm{H}_3\mathrm{O}^+

    • This equation correctly represents the dissociation of acetic acid in water, forming acetate and hydronium ions.
  3. CH3COOH+H2OCH3CHCOOH2++OH\mathrm{CH}_3\mathrm{COOH} + \mathrm{H}_2\mathrm{O} \rightleftharpoons \mathrm{CH}_3\mathrm{CHCOOH}_2^+ + \mathrm{OH}^-

    • This equation incorrectly suggests the formation of a different ion and hydroxide, which is not typical for carboxylic acid dissociation.
  4. CH3COOH+H3O+CH3COOH2++H2O\mathrm{CH}_3\mathrm{COOH} + \mathrm{H}_3\mathrm{O}^+ \rightleftharpoons \mathrm{CH}_3\mathrm{COOH}_2^+ + \mathrm{H}_2\mathrm{O}

    • This equation suggests protonation of acetic acid, which is not the dissociation process.
  5. CH3COOH+2H2OCH3COO2+2H3O+\mathrm{CH}_3\mathrm{COOH} + 2 \mathrm{H}_2\mathrm{O} \rightleftharpoons \mathrm{CH}_3\mathrm{COO}^{2-} + 2 \mathrm{H}_3\mathrm{O}^+

    • This equation incorrectly suggests the formation of a doubly charged acetate ion, which is not typical.

Final Answer

The correct equation representing the dissociation of a carboxylic acid in water is:

CH3COOH+H2OCH3COO+H3O+ \boxed{\mathrm{CH}_3\mathrm{COOH} + \mathrm{H}_2\mathrm{O} \rightleftharpoons \mathrm{CH}_3\mathrm{COO}^- + \mathrm{H}_3\mathrm{O}^+}

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