To rationalize the expression, multiply and divide by the conjugate of the numerator: \(\frac{\sqrt{x+3} + sqrt(3)}{\sqrt{x+3} + sqrt(3)}\). This gives us:
\[\frac{\left(\sqrt{x+3} - sqrt(3)\right)\left(\sqrt{x+3} + sqrt(3)\right)}{x\left(\sqrt{x+3} + sqrt(3)\right)} = \frac{\sqrt{x + 3} - \sqrt{3}}{x}\]
Step 2: Direct Substitution
After simplification, we directly substitute \(x = 0\) into the simplified expression to find the limit.
\[\lim_{x \to 0}\frac{\sqrt{x + 3} - \sqrt{3}}{x} = 0.289\]