Questions: (sum xi)^2=(1.75+2.76+ldots+1.96)^2=(112.15 times 10.59)^2 We can now use sum xi^2=23.1547,(sum xi)^2=(10.59)^2, and n=5 to calculate s^2. (Round the variance to four decimal places.) s^2 =fracsum xi^2-frac(sum xi)^2nn-1 = frac23.1547-frac(10.59)^25square x = square

$(sum xi)^2=(1.75+2.76+ldots+1.96)^2=(112.15 times 10.59)^2 We can now use sum xi^2=23.1547,(sum xi)^2=(10.59)^2, and n=5 to calculate s^2. (Round the variance to four decimal places.) s^2 =fracsum xi^2-frac(sum xi)^2nn-1 = frac23.1547-frac(10.59)^25square x = square$

Transcript text: \[ \left(\sum x_{i}\right)^{2}=(1.75+2.76+\ldots+1.96)^{2}=(112.15 \times 10.59)^{2} \] We can now use $\sum x_{i}^{2}=23.1547,\left(\sum x_{i}\right)^{2}=(10.59)^{2}$, and $n=5$ to calculate $s^{2}$. (Round the variance to four decimal places.) \[ \begin{aligned} s^{2} & =\frac{\sum x_{i}^{2}-\frac{\left(\sum x_{i}\right)^{2}}{n}}{n-1} \\ & =\frac{23.1547-\frac{(10.59)^{2}}{5}}{\square x} \\ & =\square \end{aligned} \]