To find the intercepts of the line given by the equation \(7x - 4y = 28\):
To find the \(x\)-intercept, we set \(y = 0\) in the equation \(7x - 4y = 28\):
\[ 7x - 4(0) = 28 \implies 7x = 28 \implies x = \frac{28}{7} = 4 \]
Thus, the \(x\)-intercept is \(4\).
To find the \(y\)-intercept, we set \(x = 0\) in the equation \(7x - 4y = 28\):
\[ 7(0) - 4y = 28 \implies -4y = 28 \implies y = \frac{28}{-4} = -7 \]
Thus, the \(y\)-intercept is \(-7\).
The \(x\)-intercept is \(\boxed{4}\) and the \(y\)-intercept is \(\boxed{-7}\).
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