Questions: Solve for x .
[
sqrt3 x-1=7
]
What is the root? If there is no root, choose none.
16 2/3
16
12
none
Transcript text: Solve for x .
\[
\sqrt{3 x-1}=7
\]
What is the root? If there is no root, choose none.
$16 \frac{2}{3}$
16
12
none
Solution
Solution Steps
To solve the equation \(\sqrt{3x - 1} = 7\), we need to eliminate the square root by squaring both sides of the equation. This will give us a linear equation in terms of \(x\). After solving for \(x\), we should verify if the solution satisfies the original equation.
Step 1: Eliminate the Square Root
We start with the equation:
\[
\sqrt{3x - 1} = 7
\]
To eliminate the square root, we square both sides:
\[
3x - 1 = 7^2
\]
This simplifies to:
\[
3x - 1 = 49
\]
Step 2: Solve for \(x\)
Next, we isolate \(x\) by adding 1 to both sides:
\[
3x = 49 + 1
\]
This gives us:
\[
3x = 50
\]
Now, we divide both sides by 3:
\[
x = \frac{50}{3}
\]
Step 3: Verify the Solution
We need to verify that our solution satisfies the original equation. Substituting \(x = \frac{50}{3}\) back into the original equation:
\[
\sqrt{3\left(\frac{50}{3}\right) - 1} = \sqrt{50 - 1} = \sqrt{49} = 7
\]
Since both sides are equal, our solution is valid.
Final Answer
The solution to the equation is
\[
\boxed{x = \frac{50}{3}}
\]