Graph the function \( f(x) = \frac{1}{4}x + 9 \).
Find the y-intercept.
The y-intercept is the value of \(f(x)\) when \(x = 0\).
\(f(0) = \frac{1}{4}(0) + 9 = 9\).
So the y-intercept is \((0, 9)\).
Find the x-intercept.
The x-intercept is the value of \(x\) when \(f(x) = 0\).
\(0 = \frac{1}{4}x + 9\)
\(-9 = \frac{1}{4}x\)
\(x = -36\)
So the x-intercept is \((-36, 0)\).
Plot the intercepts and draw the line.
Plot the points \((0, 9)\) and \((-36, 0)\) on the coordinate plane. Draw a straight line through these two points. This is the graph of the function \(f(x) = \frac{1}{4}x + 9\).
\( \boxed{\text{The graph of the function passes through } (0, 9) \text{ and } (-36, 0)} \)
\( \boxed{\text{The graph of the function passes through } (0, 9) \text{ and } (-36, 0)} \)