Questions: Olive has 3 fair coins. She will toss each coin one time. What is the probability that all 3 coins will land with "heads" facing up? A 1/2 B 1/4 C 1/6 D 1/8

Olive has 3 fair coins. She will toss each coin one time. What is the probability that all 3 coins will land with "heads" facing up?

A 1/2
B 1/4
C 1/6
D 1/8
Transcript text: Olive has 3 fair coins. She will toss each coin one time. What is the probability that all 3 coins will land with "heads" facing up? A $\frac{1}{2}$ B $\quad \frac{1}{4}$ C $\quad \frac{1}{6}$ D $\quad \frac{1}{8}$
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Solution

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Solution Steps

Step 1: Understand the problem

Olive has 3 fair coins, and she will toss each coin one time. We need to find the probability that all 3 coins will land with "heads" facing up.

Step 2: Determine the probability of a single coin landing on heads

Since each coin is fair, the probability of a single coin landing on heads is: \[ P(\text{Heads}) = \frac{1}{2} \]

Step 3: Calculate the probability of all 3 coins landing on heads

Since the coin tosses are independent events, the probability of all 3 coins landing on heads is the product of the probabilities of each individual coin landing on heads: \[ P(\text{All Heads}) = P(\text{Heads}) \times P(\text{Heads}) \times P(\text{Heads}) = \left(\frac{1}{2}\right)^3 = \frac{1}{8} \]

Final Answer

The probability that all 3 coins will land with "heads" facing up is: \[ \boxed{\frac{1}{8}} \]

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