Questions: Olive has 3 fair coins. She will toss each coin one time. What is the probability that all 3 coins will land with "heads" facing up?
A 1/2
B 1/4
C 1/6
D 1/8
Transcript text: Olive has 3 fair coins. She will toss each coin one time. What is the probability that all 3 coins will land with "heads" facing up?
A $\frac{1}{2}$
B $\quad \frac{1}{4}$
C $\quad \frac{1}{6}$
D $\quad \frac{1}{8}$
Solution
Solution Steps
Step 1: Understand the problem
Olive has 3 fair coins, and she will toss each coin one time. We need to find the probability that all 3 coins will land with "heads" facing up.
Step 2: Determine the probability of a single coin landing on heads
Since each coin is fair, the probability of a single coin landing on heads is:
\[
P(\text{Heads}) = \frac{1}{2}
\]
Step 3: Calculate the probability of all 3 coins landing on heads
Since the coin tosses are independent events, the probability of all 3 coins landing on heads is the product of the probabilities of each individual coin landing on heads:
\[
P(\text{All Heads}) = P(\text{Heads}) \times P(\text{Heads}) \times P(\text{Heads}) = \left(\frac{1}{2}\right)^3 = \frac{1}{8}
\]
Final Answer
The probability that all 3 coins will land with "heads" facing up is:
\[
\boxed{\frac{1}{8}}
\]