Questions: A copper atom has a mass of 1.06 × 10^-22 g and a penny has a mass of 2.5 g. Use this information to answer the question below. Be sure your answers have the correct number of significant digits. What is the mass of 1 mole of copper atoms? Round your answer to 3 significant digits.

Solution Steps

A mole of any substance contains Avogadro's number of atoms, which is \(6.022 \times 10^{23}\) atoms.

Given the mass of one copper atom is \(1.06 \times 10^{-22} \, \text{g}\), we can find the mass of one mole of copper atoms by multiplying the mass of one atom by Avogadro's number: \[ \text{Mass of 1 mole of copper atoms} = 1.06 \times 10^{-22} \, \text{g} \times 6.022 \times 10^{23} \, \text{atoms/mole} \]

\[ \text{Mass of 1 mole of copper atoms} = 1.06 \times 6.022 \times 10^{-22 + 23} \, \text{g} \] \[ = 6.38332 \times 10^1 \, \text{g} \]

Rounding \(6.38332 \times 10^1 \, \text{g}\) to 3 significant digits, we get: \[ = 63.8 \, \text{g} \]

Final Answer