Questions: The following data represent the flight time (in minutes) of a random sample of six flights from Las Vegas, Nevada, to Newark, New Jersey, on United Airlines.
282, 260, 266, 257, 260, 267
Compute the range and sample standard deviation of flight time.
The range of flight time is 25 minutes.
The sample standard deviation of flight time is minutes.
(Type an integer or decimal rounded to one decimal place as needed.)
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Question 6, 3.2.14
Part 2 of 2
HW Score: $25 \%$,
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The following data represent the flight time (in minutes) of a random sample of six flights from Las Vegas, Nevada, to Newark, New Jersey, on United Airlines.
\[
282,260,266,257,260,267
\]
Compute the range and sample standard deviation of flight time.
The range of flight time is 25 minutes.
The sample standard deviation of flight time is $\square$ minutes.
(Type an integer or decimal rounded to one decimilal place as needed.)
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Solution
Solution Steps
Step 1: Compute the Range (R)
To calculate the range, we identify the maximum ($d_{max}$) and minimum ($d_{min}$) flight times in the dataset.
Given dataset: $D = \{282, 260, 266, 257, 260, 267\}$
$d_{max} = 282$ minutes, $d_{min} = 257$ minutes
The range ($R$) is calculated as $R = d_{max} - d_{min} = 282 - 257 = 25$ minutes.
Step 2: Compute the Sample Standard Deviation (s)
The mean ($\mu$) of the dataset is calculated as $\mu = \frac{1}{n} \sum_{i=1}^{n} d_i = \frac{1}{6} \times 1592 = 265.333$.
The variance ($s^2$) is calculated using the formula $s^2 = \frac{1}{n-1} \sum_{i=1}^{n} (d_i - \mu)^2$.
Substituting the values, we get $s^2 = \frac{1}{6-1} \times 407.333 = 81.467$.
The sample standard deviation ($s$) is the square root of the variance: $s = \sqrt{s^2} = \sqrt{81.467} = 9$.
Final Answer:
The range of the dataset is 25 minutes, and the sample standard deviation is 9 minutes (rounded to 1 decimal places).