Questions: 880.62 g ÷ 0.67 mL = □ g/mL 0.934 cm × 4.625 cm = □ cm² 371.2 g ÷ 68.383 mL = □ g/mL

Solution Steps

For each calculation, we need to determine the number of significant digits in the given measurements:

1. \( 880.62 \mathrm{~g} \div 0.67 \mathrm{~mL} \)

   • \( 880.62 \mathrm{~g} \) has 5 significant digits.
   • \( 0.67 \mathrm{~mL} \) has 2 significant digits.

2. \( 0.934 \mathrm{~cm} \times 4.625 \mathrm{~cm} \)

   • \( 0.934 \mathrm{~cm} \) has 3 significant digits.
   • \( 4.625 \mathrm{~cm} \) has 4 significant digits.

3. \( 371.2 \mathrm{~g} \div 68.383 \mathrm{~mL} \)

   • \( 371.2 \mathrm{~g} \) has 4 significant digits.
   • \( 68.383 \mathrm{~mL} \) has 5 significant digits.

1. \( 880.62 \mathrm{~g} \div 0.67 \mathrm{~mL} \) \[ \frac{880.62}{0.67} \approx 1314.5075 \frac{\mathrm{g}}{\mathrm{~mL}} \]

2. \( 0.934 \mathrm{~cm} \times 4.625 \mathrm{~cm} \) \[ 0.934 \times 4.625 \approx 4.31925 \mathrm{cm}^2 \]

3. \( 371.2 \mathrm{~g} \div 68.383 \mathrm{~mL} \) \[ \frac{371.2}{68.383} \approx 5.4285 \frac{\mathrm{g}}{\mathrm{~mL}} \]

1. \( 880.62 \mathrm{~g} \div 0.67 \mathrm{~mL} \)

   • The result should have 2 significant digits (the smallest number of significant digits in the given measurements). \[ 1314.5075 \approx 1300 \frac{\mathrm{g}}{\mathrm{~mL}} \]

2. \( 0.934 \mathrm{~cm} \times 4.625 \mathrm{~cm} \)

   • The result should have 3 significant digits (the smallest number of significant digits in the given measurements). \[ 4.31925 \approx 4.32 \mathrm{cm}^2 \]

3. \( 371.2 \mathrm{~g} \div 68.383 \mathrm{~mL} \)

   • The result should have 4 significant digits (the smallest number of significant digits in the given measurements). \[ 5.4285 \approx 5.429 \frac{\mathrm{g}}{\mathrm{~mL}} \]

Final Answer