Questions: PreCalc - Lesson Quiz 6.3
Given the rational function y=(2 x^2+15+3)/(r^4+1), this either has a horizontal asymptote or a slant asymptote. Determine which one. Then enter the correct value in the blank. For the one that doesn't exist enter 'na' in the blanks.
Horizontal: y=
Slant: y= 7.
Transcript text: PreCalc - Lesson Quiz 6.3
Given the rational function $y=\frac{2 x^{2}+15+3}{r^{4}+1}$, this either has a horizontal asymptote or a slant asymptote. Determine which one. Then enter the correct value in the blank. For the one that doesn't exist enter 'na' in the blanks.
Horizontal: $y=$ $\square$
Slant: $y=$ $\square$ 7. $\square$
Solution
Solution Steps
Step 1: Identify the degrees of the numerator and denominator
The given rational function is:
\[
y = \frac{2x^{2} + 15x + 3}{x^{4} + 1}
\]
The degree of the numerator \( 2x^{2} + 15x + 3 \) is 2.
The degree of the denominator \( x^{4} + 1 \) is 4.
Step 2: Determine the type of asymptote
For a rational function \( y = \frac{P(x)}{Q(x)} \):
If the degree of \( P(x) \) is less than the degree of \( Q(x) \), the horizontal asymptote is \( y = 0 \).
If the degree of \( P(x) \) is equal to the degree of \( Q(x) \), the horizontal asymptote is \( y = \frac{\text{leading coefficient of } P(x)}{\text{leading coefficient of } Q(x)} \).
If the degree of \( P(x) \) is greater than the degree of \( Q(x) \) by exactly 1, there is a slant asymptote.
In this case, the degree of the numerator (2) is less than the degree of the denominator (4). Therefore, there is a horizontal asymptote at \( y = 0 \), and there is no slant asymptote.
Step 3: Fill in the blanks
Horizontal asymptote: \( y = 0 \).
Slant asymptote: Does not exist, so we write "na".
Final Answer
\[
\text{Horizontal: } y = \boxed{0}
\]
\[
\text{Slant: } y = \boxed{\text{na}}
\]