Questions: frac-(-2) pm sqrt(-2)^2-4()(-3)2(-3)

Solution Steps

To solve the quadratic equation using the quadratic formula, we need to identify the coefficients $a$, $b$, and $c$ from the standard form $ax^2 + bx + c = 0$. In this case, the equation is not fully provided, but assuming it is of the form $(-3)x^2 + (-2)x + c = 0$, we can use the quadratic formula:

$$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$$

Substitute $a = -3$, $b = -2$, and $c$ (which is not provided, so we assume it to be 0 for this example) into the formula to find the roots.

The quadratic equation is assumed to be in the form $-3x^2 - 2x + c = 0$. Here, the coefficients are identified as:

• $a = -3$
• $b = -2$
• $c = 0$ (assumed since it was not provided)

The discriminant $\Delta$ is calculated using the formula: $$\Delta = b^2 - 4ac$$ Substituting the values, we get: $$\Delta = (-2)^2 - 4(-3)(0) = 4$$

The roots of the quadratic equation are given by the quadratic formula: $$x = \frac{-b \pm \sqrt{\Delta}}{2a}$$ Substituting the values of $a$, $b$, and $\Delta$, we find: $$x_1 = \frac{-(-2) + \sqrt{4}}{2(-3)} = \frac{2 + 2}{-6} = -0.6667$$ $$x_2 = \frac{-(-2) - \sqrt{4}}{2(-3)} = \frac{2 - 2}{-6} = 0$$

Final Answer