Questions: Find the volume of the solid obtained by rotating the region bounded by the curve f(x) = e^(3x)/6, the x-axis, the y-axis, and the line x=1 around the y-axis.
Submit an exact answer.
Provide your answer below:
Volume = (π/27)(2e^3+1)
Transcript text: Find the volume of the solid obtained by rotating the region bounded by the curve $f(x)=\frac{e^{3 x}}{6}$, the $x$-axis, the $y$-axis, and the line $x=1$ around the $y$-axis.
Submit an exact answer.
Provide your answer below:
\[
\text { Volume }=\frac{\pi}{27}\left(2 e^{3}+1\right)
\]
FEEDBACK
Solution
Solution Steps
To find the volume of the solid obtained by rotating the given region around the y-axis, we can use the method of cylindrical shells. The formula for the volume using cylindrical shells is:
\[ V = 2\pi \int_{a}^{b} x \cdot f(x) \, dx \]
In this problem, the region is bounded by \( f(x) = \frac{e^{3x}}{6} \), the x-axis, the y-axis, and the line \( x = 1 \). We will integrate from \( x = 0 \) to \( x = 1 \).
Solution Approach
Set up the integral for the volume using the method of cylindrical shells.
Integrate the function from \( x = 0 \) to \( x = 1 \).
Evaluate the integral to find the exact volume.
Step 1: Set Up the Integral for Volume
To find the volume of the solid obtained by rotating the region around the \( y \)-axis, we use the method of cylindrical shells. The formula for the volume is:
\[
V = 2\pi \int_{0}^{1} x \cdot \frac{e^{3x}}{6} \, dx
\]