Questions: Country A has an exponential growth rate of 3.8% per year. The population is currently 4,891,000, and the land area of Country A is 20,000,000,000 square yards. Assuming this growth rate continues and is exponential, after how long will there be one person for every square yard of land?

Country A has an exponential growth rate of 3.8% per year. The population is currently 4,891,000, and the land area of Country A is 20,000,000,000 square yards. Assuming this growth rate continues and is exponential, after how long will there be one person for every square yard of land?
Transcript text: Country A has an exponential growth rate of $3.8 \%$ per year. The population is currently $4,891,000$, and the land area of Country A is $20,000,000,000$ square yards. Assuming this growth rate continues and is exponential, after how long will there be one person for every square yard of land?
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Solution

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Solution Steps

Step 1: Convert the annual growth rate from a percentage to a decimal

To convert the growth rate to a decimal, we divide the percentage by 100: \(r = \frac{3.8}{100} = 0.038\).

Step 2: Use the formula for exponential growth

The formula for exponential growth is \(P = P_0 \times (1 + r)^t\), where \(P\) is the population at time \(t\), \(P_0\) is the initial population, \(r\) is the growth rate per period, and \(t\) is the number of periods (years).

Step 3: Solve for \(t\) when \(P = A\)

Substituting \(A\) for \(P\) and solving for \(t\), we get \(t = \frac{\log(A/P_0)}{\log(1 + r)} = 222.98\) years.

Final Answer:

The number of years required for the population to reach a density of one person per square yard of land area is approximately 222.98 years.

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