Questions: Question 43 2 points A fire fighting vehicle of mass 13,000 kg is at rest but free to roll with no resistance. If you push it forward with a force of 600 N, the momentum at the end of 10 s of pushing will be 5000 kg m / s. 0.416 m / s. 20,000 kg N / s. 6000 kg m / s.

Solution Steps

We need to calculate the momentum of a fire fighting vehicle after being pushed with a force of 600 N for 10 seconds. The vehicle is initially at rest and has a mass of 13,000 kg.

The impulse-momentum theorem states that the change in momentum of an object is equal to the impulse applied to it. Mathematically, this is expressed as:

\[ \Delta p = F \cdot \Delta t \]

where:

• \(\Delta p\) is the change in momentum,
• \(F\) is the force applied,
• \(\Delta t\) is the time duration.

Substitute the given values into the impulse-momentum equation:

\[ \Delta p = 600 \, \text{N} \times 10 \, \text{s} = 6000 \, \text{Ns} \]

Since the vehicle starts from rest, the initial momentum is zero, and the final momentum is equal to the change in momentum.

Final Answer