Questions: Determine if the following function is even, odd, or neither. f(x)=5 x^4+3 x^2 (a) f(-x)= (b) Thus f(x) is Select an answer and is symmetric to the Select an answer

Determine if the following function is even, odd, or neither.
f(x)=5 x^4+3 x^2
(a) f(-x)= 
(b) Thus f(x) is Select an answer and is symmetric to the Select an answer
Transcript text: Determine if the following function is even, odd, or neither. \[ f(x)=5 x^{4}+3 x^{2} \] (a) $f(-x)=$ $\square$ (b) Thus $f(x)$ is Select an answer $\vee$ and is symmetric to the Select an answer $\checkmark$
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Solution

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Solution Steps

To determine if a function is even, odd, or neither, we need to evaluate f(x) f(-x) and compare it to f(x) f(x) and f(x)-f(x). A function is even if f(x)=f(x) f(-x) = f(x) , odd if f(x)=f(x) f(-x) = -f(x) , and neither if it satisfies neither condition.

Step 1: Evaluate f(x) f(-x)

Given the function f(x)=5x4+3x2 f(x) = 5x^4 + 3x^2 , we substitute x-x for xx to find f(x) f(-x) : f(x)=5(x)4+3(x)2=5x4+3x2 f(-x) = 5(-x)^4 + 3(-x)^2 = 5x^4 + 3x^2

Step 2: Compare f(x) f(-x) with f(x) f(x) and f(x)-f(x)

From the evaluation, we have: f(x)=5x4+3x2=f(x) f(-x) = 5x^4 + 3x^2 = f(x) Since f(x)=f(x) f(-x) = f(x) , the function is even.

Final Answer

even\boxed{\text{even}}

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