Find \((A \cup B)^{\prime}\).
Step 1: Find \(A \cup B\).
\(A \cup B\) is the union of sets \(A\) and \(B\).
Given:
\(A = \{f, m, r, y\}\)
\(B = \{m, q, y\}\)
Thus, \(A \cup B = \{f, m, q, r, y\}\).
Step 2: Find the complement of \(A \cup B\), denoted as \((A \cup B)^{\prime}\).
The complement of a set \(S\) with respect to the universal set \(U\) is \(U \setminus S\).
Given:
\(U = \{f, m, q, r, y, z\}\)
\(A \cup B = \{f, m, q, r, y\}\)
Thus, \((A \cup B)^{\prime} = U \setminus (A \cup B) = \{z\}\).
\(\boxed{(A \cup B)^{\prime} = \{z\}}\)
Find \(A^{\prime} \cap B\).
Step 1: Find the complement of \(A\), denoted as \(A^{\prime}\).
The complement of \(A\) with respect to the universal set \(U\) is \(U \setminus A\).
Given:
\(U = \{f, m, q, r, y, z\}\)
\(A = \{f, m, r, y\}\)
Thus, \(A^{\prime} = U \setminus A = \{q, z\}\).
Step 2: Find the intersection of \(A^{\prime}\) and \(B\).
Given:
\(A^{\prime} = \{q, z\}\)
\(B = \{m, q, y\}\)
Thus, \(A^{\prime} \cap B = \{q\}\).
\(\boxed{A^{\prime} \cap B = \{q\}}\)
\(\boxed{(A \cup B)^{\prime} = \{z\}}\)
\(\boxed{A^{\prime} \cap B = \{q\}}\)