To solve these probability questions, we need to understand the composition of the boxes and the nature of probability.
a. An event with probability 1 is certain to happen. For example, if all pens in a box are of the same color, drawing that color is certain.
b. An event with probability 0 is impossible. For example, drawing a color that doesn't exist in a box.
c. Probability cannot be greater than 1, so an event with probability 3 is impossible in standard probability theory.
We have two boxes, Box A and Box B, each containing red and purple pens. We need to determine the probability of certain events based on the composition of these boxes.
For Box A, the total number of pens is:
\[ \text{Total Box A} = 10 + 23 = 33 \]
For Box B, the total number of pens is:
\[ \text{Total Box B} = 16 + 8 = 24 \]
An event with probability 1 is certain. Since both boxes contain both colors, no single color is certain to be drawn. However, if we consider the event of drawing any pen from a box, this event is certain, hence:
\[ P(\text{any pen from a box}) = 1 \]
An event with probability 0 is impossible. For example, drawing a green pen from either box is impossible since there are no green pens:
\[ P(\text{drawing a green pen}) = 0 \]
Probability cannot exceed 1 in standard probability theory. Therefore, an event with probability 3 is not possible:
\[ P(\text{any event}) \leq 1 \]
- Probability of event a: \( \boxed{1} \)
- Probability of event b: \( \boxed{0} \)
- Probability of event c: \( \boxed{\text{Not possible}} \)