Questions: Factor the following polynomial completely.
9 x^3 + 63 x^2 + 54 x
A. 9 x(x-1)(x-6)
B. 9 x(x-9)(x+6)
C. 9 x(x+1)(x+6)
D. 9 x(x+9)(x+6)
Transcript text: Factor the following polynomial completely.
\[
9 x^{3}+63 x^{2}+54 x
\]
A. $9 x(x-1)(x-6)$
B. $9 x(x-9)(x+6)$
C. $9 x(x+1)(x+6)$
D. $9 x(x+9)(x+6)$
Solution
Solution Steps
To factor the polynomial \(9x^3 + 63x^2 + 54x\) completely, we first look for the greatest common factor (GCF) of all the terms. Then, we factor out the GCF and factor the remaining polynomial if possible.
Step 1: Identify the Polynomial
We start with the polynomial \(9x^3 + 63x^2 + 54x\).
Step 2: Factor Out the Greatest Common Factor (GCF)
The GCF of the terms \(9x^3\), \(63x^2\), and \(54x\) is \(9x\). We factor this out:
\[
9x^3 + 63x^2 + 54x = 9x(x^2 + 7x + 6)
\]
Step 3: Factor the Quadratic Expression
Next, we need to factor the quadratic expression \(x^2 + 7x + 6\). We look for two numbers that multiply to \(6\) and add to \(7\). These numbers are \(1\) and \(6\). Thus, we can factor the quadratic as:
\[
x^2 + 7x + 6 = (x + 1)(x + 6)
\]
Step 4: Combine the Factors
Now, we can combine the factors:
\[
9x(x^2 + 7x + 6) = 9x(x + 1)(x + 6)
\]
Final Answer
The completely factored form of the polynomial is:
\[
\boxed{9x(x + 1)(x + 6)}
\]